Ko Man Bun :略
遇高手了,等我搵日搵返d數學試卷出黎研究下先

頭先跌落谷底,但係而家心情勁靚

(t#573934)
板主: 葵芳站總站站務助理員
Ko Man Bun :略
Ko Man Bun :3a)
c^2-10c+25
=(c-5)(c-5)
=(c-5)^2
3b)
c^2-10c+25+cd-5d
=(c-5)^2+d(c-5) [By using the results of (a)]
=(c-5)(c-5)+d(c-5)
=(c-5)(c-5+d)
GU1776@34 :Btw鯊魚兄你F2??
Shark! :唔識做
Ko Man Bun :3a)
c^2-10c+25
=(c-5)(c-5)
=(c-5)^2
3b)
c^2-10c+25+cd-5d
=(c-5)^2+d(c-5) [By using the results of (a)]
=(c-5)(c-5)+d(c-5)
=(c-5)(c-5+d)
點解 3a 係 (c-5)(c-5) 嘅GU1776@34 :Btw鯊魚兄你F2??
Yes , 頹成咁好易留班![]()
![]()
![]()
![]()
![]()
![]()
btw 係 BF 仲要見到呢啲數真係想死咁制![]()
![]()
玩 Identity 好啲
GU1776@34 :Shark! :唔識做
Ko Man Bun :3a)
c^2-10c+25
=(c-5)(c-5)
=(c-5)^2
3b)
c^2-10c+25+cd-5d
=(c-5)^2+d(c-5) [By using the results of (a)]
=(c-5)(c-5)+d(c-5)
=(c-5)(c-5+d)
點解 3a 係 (c-5)(c-5) 嘅GU1776@34 :Btw鯊魚兄你F2??
Yes , 頹成咁好易留班![]()
![]()
![]()
![]()
![]()
![]()
btw 係 BF 仲要見到呢啲數真係想死咁制![]()
![]()
玩 Identity 好啲
3a依啲緊係用計數機啦![]()
點解??用Cross Method計都得嘅
GU1776@34 :Shark! :唔識做
Ko Man Bun :3a)
c^2-10c+25
=(c-5)(c-5)
=(c-5)^2
3b)
c^2-10c+25+cd-5d
=(c-5)^2+d(c-5) [By using the results of (a)]
=(c-5)(c-5)+d(c-5)
=(c-5)(c-5+d)
點解 3a 係 (c-5)(c-5) 嘅GU1776@34 :Btw鯊魚兄你F2??
Yes , 頹成咁好易留班![]()
![]()
![]()
![]()
![]()
![]()
btw 係 BF 仲要見到呢啲數真係想死咁制![]()
![]()
玩 Identity 好啲
3a依啲緊係用計數機啦![]()
點解??用Cross Method計都得嘅
Shark! :唔識做
Ko Man Bun :3a)
c^2-10c+25
=(c-5)(c-5)
=(c-5)^2
3b)
c^2-10c+25+cd-5d
=(c-5)^2+d(c-5) [By using the results of (a)]
=(c-5)(c-5)+d(c-5)
=(c-5)(c-5+d)
點解 3a 係 (c-5)(c-5) 嘅
MTR NE :人地中二炸![]()
btw而家教嘅實數虛數仲未KO到我
一時手快打錯
Shark! :What is cross Method
conlin1997 :Shark! :唔識做
Ko Man Bun :3a)
c^2-10c+25
=(c-5)(c-5)
=(c-5)^2
3b)
c^2-10c+25+cd-5d
=(c-5)^2+d(c-5) [By using the results of (a)]
=(c-5)(c-5)+d(c-5)
=(c-5)(c-5+d)
點解 3a 係 (c-5)(c-5) 嘅
其實可以用計數機計的.....
For CASIO fx-50FH:
首先:FMLA>01
之後用3a做例:
a=1,只代個代數前面個no.(c^2=1c^2)
b=-10,只上(-10c)
c=25,呢個照代入去
做完後EXE兩次,會show兩個ans.,以今次為例,出咗兩次5,係c^2-10c+25的解
由於:
c=5
c-5=0
有兩次c=5,所以(c-5)(c-5)
P.S:假如果兩個ans係唔同,好似出5同-8,
個ans.會=(c-5)(c+8)
Sor for 1999
conlin1997 :Shark! :唔識做
Ko Man Bun :3a)
c^2-10c+25
=(c-5)(c-5)
=(c-5)^2
3b)
c^2-10c+25+cd-5d
=(c-5)^2+d(c-5) [By using the results of (a)]
=(c-5)(c-5)+d(c-5)
=(c-5)(c-5+d)
點解 3a 係 (c-5)(c-5) 嘅
其實可以用計數機計的.....
For CASIO fx-50FH:
首先:FMLA>01
之後用3a做例:
a=1,只代個代數前面個no.(c^2=1c^2)
b=-10,只上(-10c)
c=25,呢個照代入去
做完後EXE兩次,會show兩個ans.,以今次為例,出咗兩次5,係c^2-10c+25的解
由於:
c=5
c-5=0
有兩次c=5,所以(c-5)(c-5)
P.S:假如果兩個ans係唔同,好似出5同-8,
個ans.會=(c-5)(c+8)
Sor for 1999MTR NE :人地中二炸![]()
btw而家教嘅實數虛數仲未KO到我
一時手快打錯
我中二已經有計數機la bo
conlin1997 :Shark! :唔識做
Ko Man Bun :3a)
c^2-10c+25
=(c-5)(c-5)
=(c-5)^2
3b)
c^2-10c+25+cd-5d
=(c-5)^2+d(c-5) [By using the results of (a)]
=(c-5)(c-5)+d(c-5)
=(c-5)(c-5+d)
點解 3a 係 (c-5)(c-5) 嘅
其實可以用計數機計的.....
For CASIO fx-50FH:
首先:FMLA>01
之後用3a做例:
a=1,只代個代數前面個no.(c^2=1c^2)
b=-10,只上(-10c)
c=25,呢個照代入去
做完後EXE兩次,會show兩個ans.,以今次為例,出咗兩次5,係c^2-10c+25的解
由於:
c=5
c-5=0
有兩次c=5,所以(c-5)(c-5)
P.S:假如果兩個ans係唔同,好似出5同-8,
個ans.會=(c-5)(c+8)
Sor for 1999MTR NE :人地中二炸![]()
btw而家教嘅實數虛數仲未KO到我
一時手快打錯
我中二已經有計數機la bo
GU1776@34 :用Formula 01不如自己入Program好過 自己入好用好多 不過 求Link 我之前俾Fd Clear Data左![]()
BTW what it 虛數?實數?
?→A: ?→B: ?→M: - B┘(2A→C: AC^2M-:
- (C+√( -M┘A))→A◢ 2C + Ans→B: - B
正在瀏覽這個板面的使用者:沒有註冊會員 和 20 位訪客