The sum of the squares of two consecutive odd numbers is less than 100. Find all the possible values of the larger odd number.

Thank you!

Let the smaller odd number ＝x,
x^2+(x+2)^2 <100
2x^2+4x-96<0
(x-6)(x+8)<0
So, -8 < x < 6
So the larger odd number can be -7,-5,-3,-1,1,3,5

Phenolphthalein :Let the smaller odd number ＝x,
x^2+(x+2)^2 <100
2x^2+4x-96<0
(x-6)(x+8)<0
So, -8 < x < 6
So the larger odd number can be -7,-5,-3,-1,1,3,5

Let the larger odd number = x,
x^2 + (x-2)^2 < 100
2x^2 - 4x - 96 < 0
(x+6) (x-8) < 0
So, -6 < x < 8
So the larger odd number can be -5, -3, -1, 1, 3, 5, 7

Phenolphthalein :Let the smaller odd number ＝x,
x^2+(x+2)^2 <100
2x^2+4x-96<0
(x-6)(x+8)<0
So, -8 < x < 6
So the larger odd number can be -7,-5,-3,-1,1,3,5

Smaller 變左larger ..
請把答案每個數+2 ...

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樓主, 好奇問一問,
依條題目屬於邊個topic?
乜唔係F.4學架咩 ???
(有錯請指 )

---

同埋,

KV9033 :

Phenolphthalein :Let the smaller odd number ＝x,
x^2+(x+2)^2 <100
2x^2+4x-96<0
(x-6)(x+8)<0
So, -8 < x < 6
So the larger odd number can be -7,-5,-3,-1,1,3,5

Let the larger odd number = x,
x^2 + (x-2)^2 < 100
2x^2 - 4x - 96 < 0
(x+6) (x-8) < 0
So, -6 < x < 8
So the larger odd number can be -5, -3, -1, 1, 3, 5, 7

(x+6) (x-8) < 0
So, -6 < x < 8

中間D steps, 請問公開試跳唔跳得?

JY4066 :

Phenolphthalein :Let the smaller odd number ＝x,
x^2+(x+2)^2 <100
2x^2+4x-96<0
(x-6)(x+8)<0
So, -8 < x < 6
So the larger odd number can be -7,-5,-3,-1,1,3,5

Smaller 變左larger ..
請把答案每個數+2 ...

---

樓主, 好奇問一問,
依條題目屬於邊個topic?
乜唔係F.4學架咩 ???
(有錯請指 )

---

同埋,

KV9033 :

Phenolphthalein :Let the smaller odd number ＝x,
x^2+(x+2)^2 <100
2x^2+4x-96<0
(x-6)(x+8)<0
So, -8 < x < 6
So the larger odd number can be -7,-5,-3,-1,1,3,5

Let the larger odd number = x,
x^2 + (x-2)^2 < 100
2x^2 - 4x - 96 < 0
(x+6) (x-8) < 0
So, -6 < x < 8
So the larger odd number can be -5, -3, -1, 1, 3, 5, 7

(x+6) (x-8) < 0
So, -6 < x < 8

中間D steps, 請問公開試跳唔跳得?

呢個係inequalities in one unknown　
f.5學的,f.4係學quadratic equation

我計到8>x>-6

let x係larger

咁答案就係-5,-3,-1,1,3,5,7

但本答案只有 3,5,7 ,所以我就問