大家好,我想問以下一組數,我咁計法岩唔岩

(以下有30組數) :45 48 52 54 55 58 58 59 61 61
62 64 65 66 66 67 70 73 75 77
77 78 79 80 82 83 86 86 91 93

Q: Construct a frequency distribution for these data. :

Number of classes
= 1 + 3.322 * log (30)
= 5.9070
= 6 (class)

Class Width
= ( 93 - 45 ) / 6
= 8

如果正確,咁就有另一個問題出現啦:

Class Limits:
45 ~ 52
53 ~ 60
61 ~ 68
69 ~ 76
77 ~ 84
85 ~ 92

咁個93係咪多左出黎?? 定係我計錯??
希望識既師兄幫幫手解答 THANK YOU..

using a class width of 10 and starting on 40 should be ok in order to record all the values

KS2234 :using a class width of 10 and starting on 40 should be ok in order to record all the values

樓主個「8」係公式俾, 所以無得改...

[我記得之前做過一條類似的數, 個老師都話>>個data係錯嫁 , 無可能做到]

不過如果用屈機方法又得唔得呢
將最細個數「45」攞佢個邊界, 即係「44.5」
將最大個數「93」攞佢個邊界, 即係「93.5」

咁....
Class Width
= ( 93.5 - 44.5 ) / 6
= 8.167
= 9

完成。